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When used as a shell builtin, this program decoded a subset of arguments

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known to printf(3) and then used printf() to format it... The only
problem what the #define printf out1fmt.  The code was behaving differently
when run as a shell builtin since out1fmt() isn't printf(3).

Simple hack.  Print to a buffer and fputs (also #defined for sh) the
result.  This should fix the printf builtin problem in PR#1673, rather
than leaving the call commented out.  (printf.o was being statically linked
in anyway, we might as well use it)
This commit is contained in:
Peter Wemm 1996-10-01 04:56:59 +00:00
parent 3e19bb8220
commit d72f654c65
Notes: svn2git 2020-12-20 02:59:44 +00:00 
svn path=/head/; revision=18613
1 changed files with 9 additions and 4 deletions
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13
usr.bin/printf/printf.c
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@ -58,15 +58,20 @@ static char sccsid[] = "@(#)printf.c 8.1 (Berkeley) 7/20/93";
#endif
#define PF(f, func) { \
char *b = NULL; \
if (fieldwidth) \
if (precision) \
(void)printf(f, fieldwidth, precision, func); \
(void)asprintf(&b, f, fieldwidth, precision, func); \
else \
(void)printf(f, fieldwidth, func); \
(void)asprintf(&b, f, fieldwidth, func); \
else if (precision) \
(void)printf(f, precision, func); \
(void)asprintf(&b, f, precision, func); \
else \
(void)printf(f, func); \
(void)asprintf(&b, f, func); \
if (b) { \
(void)fputs(b, stdout); \
free(b); \
} \
}
static int asciicode __P((void));