Use bigger I/O sizes for the memcache

There doesn't seem to be a need to limit the rx message size when
using rx_WritevAlloc.  If there arent enough rx buffers to hold
the entire message at once, it will simply return less space.

Change-Id: Ic1e99432c8e4d21c71f831b8d6aeea9f12b1c99c
Reviewed-on: http://gerrit.openafs.org/2943
Tested-by: BuildBot <buildbot@rampaginggeek.com>
Reviewed-by: Derrick Brashear <shadow@dementia.org>
Tested-by: Derrick Brashear <shadow@dementia.org>
This commit is contained in:
Chas Williams (CONTRACTOR) 2010-10-07 11:05:50 -04:00 committed by Derrick Brashear
parent 5142f16bd3
commit 6880d4a3a2

View File

@ -93,9 +93,8 @@ rxfs_storeMemPrepare(void *r, afs_uint32 size, afs_uint32 *tlen)
afs_int32 code;
struct rxfs_storeVariables *v = (struct rxfs_storeVariables *) r;
*tlen = (size > AFS_LRALLOCSIZ ? AFS_LRALLOCSIZ : size);
RX_AFS_GUNLOCK();
code = rx_WritevAlloc(v->call, v->tiov, &v->tnio, RX_MAXIOVECS, *tlen);
code = rx_WritevAlloc(v->call, v->tiov, &v->tnio, RX_MAXIOVECS, size);
RX_AFS_GLOCK();
if (code <= 0) {
code = rx_Error(v->call);